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electronic devices by floyd 7th edition solution manual

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In thi s ex periment, the large value of R E2 in both circuits makes the loading effect of the second stage on the first negligible. Therefore, the following approximation can be used for the circuits in figures 9.1 and 9.2 (the output voltage of the circuit in figure 9.2 will be inverted): The overall voltage gain A V can be found from.Most differential amplifiers are constructed as integrated circuit, but to faci li tate experimentation, we will investigate a discrete version of the same circuit. Differential amplifiers can be operated in either of two manners: the input signals can be different, or the input signals can be identical. If the input signals are different, the amplifier is said to be operating in its difference mode. This means that the output voltage w ill be proportional to the difference in the two input signals. If the input signals are the same, or the inputs are tied together, the amplifier is said to be operating in its common mode. Figure 10.1 shows a differential amplifier with small ex ternal emi tte r resistors designed to compensate for any differences in the values of r e of the two transistors. The fo ll owing equations apply to operation of the differential amplifier in its common mode when the two input signals are equal in magnitude and phase: The common mode rejection ratio ( CMRR ) is a ratio of signal gain to noise ga in that is, how we ll the amplifier amp li fies th e wanted signal and cancels the unwanted noise. The single ended. CMRR is a ratio of the single-ended difference mode voltage gain to the single -ended common-mode voltage gain. The double-ended CMRR is a ratio of the double-ended difference mode voltage gain to the doub le-ended common-mode voltage gain. Typica ll y, the CMRR is extremely high (75 to 100dB is not uncommon).Also measure the maximum resistance of the potentiometer (across its outer te rm inals). Figure 10.2 3.

With V i1 and V i2 set to 0V (grounded), connect a digital voltmeter between the outputs V O1 and V O2 so i t will read dc volts. Now adjust the 1k ? potentiometer until the voltmeter reads 0Vdc. Measure the ac voltage from the center tap of the potentiometer to ground. Connect a dual-trace oscillos cope to observe and measure the single-ended output voltages V O1 and V O2 with respect to ground. If the oscilloscope has a difference mode setting, also measure the output difference voltage ( V O1 -V O2 ). In each case note the phase relation with the input. Also calculate the dif ferential voltage gain (or double-ended voltage gain) using the same inputs. Compare thes e with the measured values obtained in procedure step 5. 3. Calculate the value of r id using the results of question 1 and the value for ?. 4. Using the results of procedure step 7, calculate the differential common mode gain and calculate the CMRR in dB. 5. What is the purpose of the common emitter stage which has the differential amp li fier in its collector circuit? ResearchGate has not been able to resolve any references for this publication. Advertisement Recommendations Discover more Project Electronics Lab.Lab is responsible for assembly and characterization of the network'sIn addition to a fully equipped CNC machineAt the heart ofSurroundingAlthough the first scienceCurrently being designed, theAdditionally, theRead more Conference Paper High frequency current fed double forward Low Voltage High Current DC-DC converter for spacecraft ap. December 2012 Shruthi Jayadev C. Lakshminayarana Sanjay Mittal A high frequency, current fed double forward Low Voltage High Current (LVHC) DC-DC converter has been designed and developed for the input power requirements of high speed digital electronic circuits such as Solid State Recorder (SSR) and Base Data Handling (BDH) sub-systems of spacecraft. The converter is developed using Surface Mount Technique (SMT) for satellite applications.

However, most of the remote laboratories today are simulated or else real, but with a fixed configuration. This scheme reduces the needed space for traditional Electronics laboratories, the staff needed to operate it, and the overall cost of equipment required, as well as allowing the lab practices to be customizable, remotely accessed through Internet, and that both the results and the changes made to the circuit be reflected in the measurements in real time. RIS BibTeX Plain Text What do you want to download. Citation only Citation and abstract Download ResearchGate iOS App Get it from the App Store now. Install Keep up with your stats and more Access scientific knowledge from anywhere or Discover by subject area Recruit researchers Join for free Login Email Tip: Most researchers use their institutional email address as their ResearchGate login Password Forgot password. Keep me logged in Log in or Continue with LinkedIn Continue with Google Welcome back. Keep me logged in Log in or Continue with LinkedIn Continue with Google No account. All rights reserved. Terms Privacy Copyright Imprint. Manual Authors: Eyad Al-kouz Princess Sumaya University for Technology Download file PDF Read file Download file PDF Read file Download citation Copy link Link copied Read file Download citation Copy link Link copied Abstract Electronics Lab.Eyad Al-Kouz Oct., 2010 I present it here as a very practical statement on how the human mind approaches the learning process: I h e ar, an d I fo rg et. I s e e, a nd I re me m b er. I d o, an d I un de r st an d. One of the best ways to understand something is to get your hands on it and actually experiment with it. In electronics, this means putting small circuits together, powering them up, and seeing first hand what they do. Table of Contents: Experiment (1): The voltage across the diode terminals determines whether or not the diode will conduct.

If the anode is more positive than the cathode, the diode will conduct current and is said to be forward-biased. Since the relationship between voltage across and current through the diode changes in this region, the diode's resistance changes.Plot I on the vertical axis and V D on the horizontal axis. 3. Determine the static resistance of the diode at 0.1V, 0.5V, and 0.6V using the values obtained for I and V D from Table 1.1. 4. Graphically determine the dynamic resistance of the diode at 0.1 V, 0.5V, and 0.6V using the I-V characteristic curve obtained in question 2. 5. Using the values obtained for I and V D from Table 1.2, calculate the static resistance of the diode at -10V. Table 1.1 In small-signal diode circuits, the changes in current and voltage occur over a very small portion of the characteristic curve of the diode. The diode is operated in its forward-biased region, which is only linear above the knee or the characteristic. (In the linear region, a small change in diode voltage yields a large change in diode current). Every possible combination or current I and voltage V D is a point which lies on this line. The quiescent current and voltage correspond to the point of intersection of the characteristic curve and the load line. The name load line comes from the fact that the slope of the line is inversely proportional to the series resistance, or load, in the circuit. Figure 2.I.1 shows how the load line is altered when the input voltage has a small ac component. When the ac component is zero, the diode current and voltage have their quiescent values, I Q and V Q. Using an oscilloscope set for ac input coupling, observe and accurately sketch the ac component of the voltage V D (t) across the diode. 4. To measure the ac voltage V R (t) across the resistor, it is necessary to interchange the diode and the resistor as shown in figure 2.I.3: Figure 2.I.3 5.

Using an oscilloscope set for ac input coupling, observe and accurately sketch the ac component or the voltage V R (t) across the resistor. Having measured V R (t), the ac Compare this graphically obtained Q point with the measured Q point from procedure step 2. 2. Using the measurements of procedure steps 2 and 5, write an expression for the total diode current i D (t). 3. Using figure 2.I.1 as a guideline, draw the peak (maximum and minimum) ac load lines on the diode characteristic. Now draw the ac component of the diode voltage V D (t) and determine the resulting current i D (t). Compare the graphically obtained i D (t) with the results obtained analytically in question 2. Experiment (2): Diode Circuits Thus, in large-signal circuits, diode operation is not confined to the linear region. This means that the diode resistance changes from a very low value to a very high one. One or the most important applications of the diode in large-signal circuits is to perform rectification, by which an alternating current is changed to a direct current. Therefore, the applied voltage must be greater than 0.7V in order for any current to flow through the load. A half-wave rectifier with graphs of applied voltage and resulting current is shown in figure 2.II.1. Figure 2.II.1 Another important application of large signal diode circuits is that of performing digital logic functions. In the AND function, the output is true (a high voltage) only if both In a typical logic circuit, an AND gate produces a 5V output only if inputs 1 and 2 are both 5V. The OR gate produces a 5V output if either input 1 or input 2 is 5V. 2. II.4 Procedure 1. To investigate the use of a diode in half-wave rectifier circuits, connect the circuit shown in fig. 2.II.2: Figure 2.II.2 2. With a dual-trace oscilloscope set for dc input coupling, measure the peak-to-peak values of the input voltage e(t) and the output voltage V R (t). Sketch both waveforms. 3. Reverse the diode terminals in figure 2.II.

2 and repeat procedure steps 2. 4. Change the input signal e(t) in figure 2.II.2 to a 5Vp-p square wave and repeat procedure step 2. 5. To investigate the use of diodes in simple digital logic gates, connect the following circuit shown in figure 2.II.3: Figure 2.II.3 6. Measure and record the values of V O at each of the combinations of values of V 1 and V 2 in Table 2.II.1. Calculate V O, assuming that each diode has a forward-biased voltage drop of 0.7V. Compare the calculated values of V O with the measured values. 5. What digital logic function is performed by the circuit in figure 2.II.3, and figure 2.II.4? V 1 (Volts ( V 2 (Volts ( V O (Volts ( 0 0 0 5 5 0 5 5 As will be demonstrated in a later experiment, the common base amplifier is also used in conjunction with FET amplifiers for high frequency amplification. When used as a small-signal amplifier; the input and output voltages and currents vary over a small range of the transistor's characteristic curves. In this situation, the amplifier is said to be operating in its Linear region, i.e. the gain of the amplifier is the same for all amplitude variations at the input and output. Small-signal amplifiers are often analyzed using ac equivalent circuits. Figure 3.I.1 shows the small-signal ac equivalent circuit of the common base amplifier in figure 3.I.3. Notice that no capacitors or dc voltage sources appear in the equivalent circuit, because they are assumed to be short-circuits to the ac signal. R 1 and R 2 in figure 3.I.3 are similarly shorted to ac ground.Adjust this potentiometer until V O is (one-half of the previous output). Remove the potentiometer and measure its resistance.Compare these with the measured values. 4. Explain the distortion observed in procedure step 6. Why does the output waveform distort when the amplitude of the input is increased above a certain value?

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